Molar mass of nitric acid
The molar mass of nitric acid (HNO₃) is 63.012 g/mol: the sum of the atomic weights 1.0080 + 14.007 + 3 × 15.999. School problems round it to 63 g/mol (H = 1, N = 14, O = 16).
Breakdown by element
M(HNO3) = 1.0080 + 14.007 + 3 × 15.999 = 63.012 g/mol
The result is rounded to the precision of the least precise atomic weight. Atomic weights from IUPAC (CIAAW). PubChem gives 63.013 g/mol: the last digit differs because the atomic weights are rounded differently. PubChem CID 944
What is nitric acid?
Nitric acid is a colourless liquid, a strong acid and a strong oxidising agent. When stored or exposed to light it turns yellow: it partly decomposes, giving off brown NO₂ gas.
It reacts with almost all metals except gold and platinum, but as a rule no hydrogen is released. Concentrated nitric acid does not dissolve iron, aluminium and chromium: it covers them with a thin protective oxide film (passivation). Nitric acid is used to make fertilisers (nitrates) and explosives.
Properties
- State at 25 °C
- Liquid
- Density
- 1.51 g/cm³ 20 °C
- Melting point
- −42 °C
- Boiling point
- 83 °C
- Solubility in water
- mixes with water in any proportion
Sources: PubChem (HSDB, NIOSH), Wikipedia (CRC Handbook), NIST Chemistry WebBook; each value agrees in two of them.
Molar mass problems with nitric acid
For school problems (H = 1, N = 14, O = 16): M(HNO₃) = 63 g/mol
Problem 1
How many moles are in 94.5 g of HNO₃?
n = m ÷ M = 94.5 g ÷ 63 g/mol
Answer: 1.5 mol
Problem 2
What is the mass of 0.1 mol of HNO₃?
m = n × M = 0.1 mol × 63 g/mol
Answer: 6.3 g
Problem 3
What is the mass percentage of N in HNO₃?
w(N) = M(N) ÷ M(HNO₃) = 14 ÷ 63 ≈ 0.222
Answer: 22.2%
Problem 4
How many molecules are in 0.5 mol of HNO₃?
N = n × NA = 0.5 mol × 6.02 × 10²³ mol⁻¹
Answer: 3.01 × 10²³
Common substances
What is molar mass?
Molar mass M is the mass of one mole of a substance, about 6.022 × 10²³ of its particles. It is measured in grams per mole (g/mol).
To find it, add up the atomic weights of all the atoms in the formula: multiply each element’s atomic weight by its subscript, the number of its atoms. In g/mol, the molar mass equals the relative molecular mass Mr.
For water: M(H₂O) = 2 × 1.0080 + 15.999 = 18.015 g/mol.